Four 1000-ohm resistors are in parallel across 100V AC. What is the power dissipated by one resistor?

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $24.99Unlock all

Study for the BCTC Industrial Maintenance Technology AMTEC – NOCTI Mechatronic Assessment. Prepare with comprehensive question sets and detailed explanations. Ensure success with our targeted practice!

Multiple Choice

Four 1000-ohm resistors are in parallel across 100V AC. What is the power dissipated by one resistor?

Explanation:
In a parallel circuit, every resistor experiences the same voltage across it, so each 1 kΩ resistor sees 100 V (use the RMS value for AC power calculations). The power dissipated by one resistor is P = V^2 / R. Plugging in the numbers: P = 100^2 / 1000 = 10 W. For context, the total power in the branch would be four times that, since each resistor draws the same power, giving 40 W in total (I per resistor is 100 V / 1000 Ω = 0.1 A, and total current is 0.4 A; P_total = V × I_total = 100 × 0.4 = 40 W).

In a parallel circuit, every resistor experiences the same voltage across it, so each 1 kΩ resistor sees 100 V (use the RMS value for AC power calculations). The power dissipated by one resistor is P = V^2 / R. Plugging in the numbers: P = 100^2 / 1000 = 10 W.

For context, the total power in the branch would be four times that, since each resistor draws the same power, giving 40 W in total (I per resistor is 100 V / 1000 Ω = 0.1 A, and total current is 0.4 A; P_total = V × I_total = 100 × 0.4 = 40 W).

More Multiple Choice Questions
Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy